In a gas discharge tube if 3 × × 10 18 electrons are flowing per sec from left to right and 2 × × 10 18 protons are flowing per second from right to left through a given cross section the magnitude and direction of current through the cross section
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As current is rate of flow of charge in the direction in which positive charge will move, the current due to electron will be i e = 
= 3 × × 10 18 × × 1.6 × × 10 − − 19 = 0.48 A (Opposite to the motion of electrons, i.e. right to left)
Current due to protons, i p = 
= 2 × × 10 18 × × 1.6 × × 10 − − 19
= 0.32 A (Right to left) so total I = i e + i p
= 0.48 + 0.32 = 0.80 A (Right to left)
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